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/ Problem of the word money: five students each brought a little money with them in class. More …?

Students are Alexis, Brittany, Christopher, Olivia and Anna-hundred-Alexis Christopher has a dollar-nickel-Anna Olivia-quarters of Britain was dimes 1.christopher has 5 more coins 2.brittany Olivia has more than 29 pieces Olivia 3. the value of currencies of Anna 12.25 worth less the value of parts 4.brittany Alexis, Olivia, and Christopher 4.45 have the total value of the currency, 5. Alexis has 21 pieces in less than Anna has no idea how to find how many of each student must really need help please explain and work through:)

Here is Part One: Rewrite the following tracks: 1,2,4. 1. Chris = .05 + Olivia (you know who has 5 more money – and therefore cents is 5 cents more) 2. Britain = 2.9 + Olivia (you know you have more than 29 rooms – and dimes to what amounts to $ 2.90 more. 4. Britain + Chris + Olivia = 4.45 now replace the formulas of Brittany and Chris (re 1 and 2) Form 4 rewritten: (2.9 + Olivia) + (.05 + Olivia) = 4.45 + Olivia Olivia recalls remains now account an amount not to add the amount to multiply on their own (have quarters – to add 25 multiply next to your name) (2.9 + (Ox.25)) + (.05 + (Ox.25)) + (Ox.25) = 4.45 now the order of operations combined as "figures". You Olivia x .25 three times and .05 + 2.9 2.95 + 3 (Olivia x .25) = 4.45 Subtract 2.95 3 (.25 x Olivia) = 1.5 divided by Olivia 3 x 25 = .5 divided by 25 = 2 – has 2 bedrooms, which now amount to 50 cents again rewrote the formulas 1 and 2 and insert your information known Chris Olivia = .05 (5 cents more) + Olivia Olivia is 50 cents + .05 = .55 cents = 55 cents Great Britain = 2.90 (29 dimes or more) + Olivia Olivia is 50 cents + 2.9 Dimes = $ 3.4 = 34 opinion now in Form 4 responses: 3.4 (34 dimes) + .50 (2 quarters) + .55 (55 pence) = 4.45

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